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<X_HW_WebUserInfoInstance InstanceID="1" ModifyPasswordFlag="0" UserName="user", f5 `* q4 P0 M: I' y4 G
Password="$2{O+XAE4\%Q8Hz@5tS/m8yQDgSY0yR.1DKNIo>@q'W/ZO7b-H\<{@lu6Vm
$ Q0 N& \6 L u# G( ``1A8+!F2v'*-Few{DK[~"5=ch-'*L'1N*Cd=<)$1mJ-$" UserLevel="
& P5 T; _5 G1 z! s8 o; G$ W: Y1" Enable="1" Alias="cpe-1" PassMode="3" Salt="118c5ee83600f818b44f80be"/>/ ` o H+ V# }& `9 y8 \% g: S
<X_HW_WebUserInfoInstance InstanceID="2" ModifyPasswordFlag="1" UserName="CMCCAd
; Q9 n1 j9 y0 Y+ _' b! Smin" Password="$2aP306GX`)~juy:Mf(*2Qdw\{/D6X"VDb>w/TI"e4*#ihWkViOP
% r. b Z4 x9 _zJn@,R+lKCN}.(~w:p4R:E3A2v0OV6gmblPn5cC7(ZkEU8s#GD$" UserLevel="0" Enable="1" Al
/ \9 o- C7 P' m: @3 g9 s X: e2 eias="cpe-2" PassMode="3" Salt="361949295549c0f4c70547c1"/>
- a5 {2 l8 x! q4 `- t5 p7 dWAP(Dopra Linux) # rm mycfg.xml B% d2 |4 ?1 Z5 F* T
WAP(Dopra Linux) #1 o6 g J8 l- i' J8 \/ M% _& c& U
# K' m- G# c6 A9 w8 ~9 I" K( E上面是得到的数据 $2aP306GX`)~juy:Mf(*2Qdw\{/D6X"VDb>w/TI"e4*#ihWkViOP
9 L2 x3 X- }& `+ v1 F! Y, P% XzJn@,R+lKCN}.(~w:p4R:E3A2v0OV6gmblPn5cC7(ZkEU8s#GD$ 使用这个解密一直不对 求正确解码 谢谢
0 P+ g; ^+ v8 K$ k) I, o5 ~. T% O6 |# A$ ~3 M1 }) s
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